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81z^2-4=0
a = 81; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·81·(-4)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*81}=\frac{-36}{162} =-2/9 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*81}=\frac{36}{162} =2/9 $
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